sunk818
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October 31, 2017, 03:02:51 PM |
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the --usb flag to limit the number of sticks per instance so he could divide them up into high and low spec sticks. Within the last couple weeks.
Although I do like that it's mentioned in the first post. The answer to at least half of people's questions is "read the first post". The --usb mentioned in the first post is cryptic. I don't fault you guys. Support & documentation is usually the last thing anyone wants to do... you've done a fine job supporting everyone!
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stealthshadow
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October 31, 2017, 05:02:05 PM |
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hello guys, nobody knows the resistance of the voltage adjustment screw, because i have brokit. Because I would like to replace it with a simple resistance.
thanks
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sidehack
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October 31, 2017, 05:13:59 PM |
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R=(9.8V-12.4)/(2-V)
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stealthshadow
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October 31, 2017, 06:32:37 PM |
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R=(9.8V-12.4)/(2-V)
so : ( 9.8 - 12.4) / (2 - 1.26) = 2.6 / 0.74 = 3.5 ohm that's it or 9.8 / 0.74 = 13 ohm
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sidehack
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October 31, 2017, 10:14:55 PM |
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My inner teacher says, "F".
Also I forgot to specify, this gives the answer in Kohm. But that doesn't change your grade.
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xhomerx10
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November 01, 2017, 03:03:12 AM |
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R=(9.8V-12.4)/(2-V)
so : ( 9.8 - 12.4) / (2 - 1.26) = 2.6 / 0.74 = 3.5 ohm that's it or 9.8 / 0.74 = 13 ohm Pick a voltage ie 1.5 and substitute for V; R=(9.8V-12.4)/(2-V) R=(9.8(1.5)-12.4)/(2 -(1.5)) R=4.6 kΩ Did I pass?
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sidehack
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November 01, 2017, 03:06:20 AM |
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Spot on.
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der_wasi
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November 01, 2017, 08:57:01 AM |
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For what it´s worth, I didn´t understand the formular either. And I´m a certified electrical engineer. Thanks for making it clear xhomerx10.
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sidehack
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November 01, 2017, 12:20:46 PM |
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I gave him an F not for not understanding the formula, but for sucking at algebra. Dropping variables, losing signs, not terribly encouraging.
If you want to know what Resistance sets a particular Voltage, you wind up with R as a function of V. So the formula was R as a function of V. That's 8th grade level stuff. It's part of my character to not do people's homework for them; if you ask me for help I'll help you but I won't do all the work for you.
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sidehack
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November 01, 2017, 12:50:13 PM |
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Cool, you created new ASICs built for other algorithms and made them both signal- and pin-compatible with the BM1384 and then swapped them onto the stick and got it working? I bet that was difficult.
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der_wasi
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November 01, 2017, 01:49:22 PM |
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I gave him an F not for not understanding the formula, but for sucking at algebra. Dropping variables, losing signs, not terribly encouraging.
It´s fine. And you´re right. What confused me was the "V". In electrotechniques, as I think you will know, it stands for Voltage. So first I thought you mean 9.8 Volt by 9.8V. But now I´m curiuos. What voltage range is possible? I think the maximum is 3.3V, right? What´s the minimum? Do you calculate with 0?
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sidehack
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November 01, 2017, 01:52:40 PM |
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The stick has a 10K pot on it, which gives you about 1.2 to 1.6 volts. The buck driver is good up to 2V and if you can supply it with enough power without ruining the USB jack, the circuit should output up to 17A.
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pete.buchwald
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November 01, 2017, 02:23:59 PM |
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[Sidehack - fyi] Obviously I'm not that clever. Now that I'm more awake and have my second cup of coffee in me, I can see that the website mines for bitcoin and instantly converts it the currency of your choice. But it's still pretty cool in my book! Watch the monera pour in, in real time in the video (with just one GekkoSci Pac2). Sure it's fractions of a penny, but it still constantly pours!! And free coin every day? ... bonus!
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sidehack
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November 01, 2017, 02:47:35 PM |
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Well that's good. The options were either some kind of multipool or some kind of scam, good to know it's the former.
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johannesfritz
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November 01, 2017, 04:31:00 PM |
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Okay well it's recognizing it then. Do you have a means of gauging how much power it draws from the USB port when it's plugged in? Should pull 1.8W to start; if it's only drawing ~30mA there's an issue with the main regulator, and ~50mA it's probably a string reset issue - which has a variety of potential causes.
The only time I see "failed usb_init" is before I put the product string and serial number on the CP2102, or if a stick is plugged in at the wrong time in the detection cycle (but it's then properly detected on the next one).
Alright, I inserted the device into a different Windows machine - and it initialized. So, the prob must be with my win7 machine. I'm building a second rig anyway, so I'll just try to run the 2pac with that one. Thanks for your help, though!
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sunk818
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November 02, 2017, 04:51:00 AM |
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Well that's good. The options were either some kind of multipool or some kind of scam, good to know it's the former.
You can also exchange Bitcoin for other coins easily with ShapeShift ( https://shapeshift.io/#/coins). Some guy has customized CoinHive Javascript to point to a different XMR pool, then let's you exchange XMR to BTC or other altcoin. If I spent $100 for three 2Pac, make $0.05 a day... it'll take me about 5 years to break even before electricity. We are doing this for fun and to learn, right?
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boardinsnowman
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November 02, 2017, 03:44:43 PM |
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And knowledge is power!
Also you're talking $.05 in today's money. If bitcoin goes up 100x in 5-10 years, you will have been making $5/day.
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sunk818
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November 02, 2017, 05:09:28 PM |
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And knowledge is power!
Also you're talking $.05 in today's money. If bitcoin goes up 100x in 5-10 years, you will have been making $5/day.
0.015 BTC minimum payout from a pool... $0.05 today gonna take 5 years and 9 months. Better keep mining for 5 years and 9 months!
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the__searcher
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November 02, 2017, 08:24:41 PM |
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Can you mine SHA3 with the Gekko or is it only limited to SHA ?
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sidehack
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November 02, 2017, 09:45:47 PM |
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Is SHA3 mathematically identical to Bitcoin's algorithm?
That wert, art and evermore shall be the answer to every question of the form "Can you mine xxx with this?" And henceforth that question will never again be answered except in this extremely sarcastic manner.
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